Physics Kinetic Theory of Gases Law of Equipartition of Energy and Internal Energy MCQ (Single Correct)

Match the column

Column-I

Column-I

(i) Diatomic molecule

[A] Internal energy= RT

(ii) f degree of freedom

[B] Work done is maximum

(iii) Adiabatic process

[C] Cp = 3.5 R

(iv) Isobaric expansion

[D] Fast and isolated system

[E]Constraints= 3 N – f

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Ans.

(i) [C]

(ii) [A],[E]

(iii) [D]

(iv) [B]

Sol.

Any diatomic molecule has 5 degrees of freedom

∴ C V = R

and C p = C V + R = R = 3.5 R

So, → (R).

If there are f degree of freedom, internal energy will be RT since each degree of freedom

contributes RT of energy per mole to the internal energy.

So, → (P)

Since f = 3N – K where K represents constraints.

K = 3N – f

So, → (T)

Adiabatic processes are fast and do not allow exchange of heat energy ( Δ Q = 0)

So, → (S)

In an isobaric process from certain situation, work done will be maximum.

So, → (Q).

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